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Equilibrium Physics by Axthe answer should be 150 newton...atleast tht's the way the numbers work out , 2/3 of the tension in each string holds up the total weight so 2 x 2/3 x tension holds up 200newton solve to get tension =150.. my bad ... use g=9.8 not 10 the two cables hold up not 200 newton but 196 newton.. u'd get the answer... |
| September 24, 2009 | 8:40 pm | Report abuse | Reply |
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Equilibrium Physics by bart6500@pacbell.net The cables each mark the hypotenuse of right triangles with the 2 m drop being one leg. The other leg must be: √(3^2 - 2^2) = √5 in length. The angles that the cables make with the ceiling are θ = Arcsin (2/3) and (180 - θ) Both the horizontal and vertical forces speaker must balance. For the horizontal forces, that means: T(1) cos θ + T(2) cos (180 - θ) = 0 (cos 180 - θ = -cos θ) T(1) cos θ - T(2) cos θ = 0 T(1) cos θ = T(2) cos θ T(1) = T(2) for any value of θ The two tensions must be equal; I'll just use T from here on out. The horizontal forces are gravity, 20 kg times -9.8 m/s^2 = 196 N and T sin θ + T sin (180 - θ). Since sin θ and sin (180 - θ) are the same, -196 N + 2T sin θ = 0 -196 + 2T (2/3) = 0 (4/3)T = 196 T = 147 N |
| September 24, 2009 | 3:31 pm | Report abuse | Reply |
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Equilibrium Physics by J Mac well what you have to do is figure out the angle those cables make because you have to use the equation F=ma but because it is not straight down you have to use F=m(sine angle)a. what you have to do is make a right triangle. the hypotenuse is 3meters and it said it hangs down 2 metes so thats the other side and you can use that to figure out the 3rd side then you can also figure out the angles. hopefully that makes sense to you and helps you out a lot. |
| September 24, 2009 | 9:45 am | Report abuse | Reply |
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Equilibrium Physics by Madhukar Daftary Let θ = angle made by the cables with the vertical and T = tension in the cable => 2T cos θ = 20 * 9.8 => 2T (2/3) = 196 => T = 196 * (3/4) = 147 N |
| September 24, 2009 | 3:11 am | Report abuse | Reply |
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Equilibrium Physics by Matt A 20 kg loudspeaker is suspended 2.0 m below the ceiling by two 3.0-m-long cables that angle outward at equal angles. What is the tension in the cables? The answer is 147N but I have no idea how to get that... |
| September 23, 2009 | 9:30 pm | Report abuse | Reply |
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